Match List I with List II ( List-I List-II (Molecule) (Shape) A. Fe_4 [ Fe(CN)_6]_3 · xH_2 O I. Violet B. [ Fe(CN)_5 NOS^ 4- . II. Blood Red A C. [Fe(SCN)]^ 2+ III. Prussian Blue D. (NH_4)_3 PO_4 · 12 MoO_3 IV. Yellow )

Correct answer: A. A-III, B-I, C-II, D-IV Fe_4[Fe(CN)_6]_3 · xH_2 O arrow Prussian Blue [Fe(CN)_5 NOS]^ 4- arrow Violet [Fe(SCN)]^ 2+ arrow Blood Red (NH_4)_3 PO_4 · 12 MoO_3 arrow Yellow

JEE Main 20248 AprilMorning Shift

Exam: JEE Main
Year: 2024
Date: 8 April
Shift: Morning Shift
Subject: Chemistry
Chapter: Chemical Bonding and Molecular Structure

JEE Main 2024 · 8 April · Morning Shift · Chemistry · Chemical Bonding and Molecular Structure

Match List I with List II ( List-I List-II (Molecule) (Shape) A....

Match List I with List II (

	List-I		List-II
	(Molecule)		(Shape)
A.	Fe_4 $\left[$ Fe(CN)_6\right]_3 $\cdot$ xH_2 O	I.	Violet
B.	{\left[ $Fe(CN)_5 NOS^{4-}\right.}</td><td>II.</td><td>Blood Red A</td></tr><tr><td>C.</td><td>{[Fe(SCN)]^{2+}}</td><td>III.</td><td>Prussian Blue</td></tr><tr><td>D.</td><td>$ \left(NH_4\right)_3 PO_4 $\cdot$ 12 MoO_3	IV.	Yellow

) Choose the correct answer from the options given below:

Options

AA-III, B-I, C-II, D-IV
BA-I, B-II, C-III, D-IV
CA-IV, B-I, C-II, D-III
DA-II, B-III, C-IV, D-I

Correct answer

A. A-III, B-I, C-II, D-IV

Step-by-step solution

\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3 \cdot \mathrm{xH}_2 \mathrm{O} \rightarrow

Prussian Blue

\left[\mathrm{Fe}(\mathrm{CN})_5 \mathrm{NOS}\right]^{4-} \rightarrow

Violet

[\mathrm{Fe}(\mathrm{SCN})]^{2+} \rightarrow

Blood Red

\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4 \cdot 12 \mathrm{MoO}_3 \rightarrow

Yellow

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