JEE Main202226 Jun 2022Morning ShiftChemistryChemical Bonding and Molecular StructureActual
Consider the ions/molecule O 2 + , O 2 , O 2 - , O 2 2 - . For increasing bond order the correct option is
Options
- AO 2 - < O 2 2 - < O 2 < O 2 +
- BO 2 - < O 2 2 - < O 2 + < O 2
- CO 2 - < O 2 + < O 2 2 - < O 2
- DO 2 2- < O 2 - < O 2 < O 2 +
Correct answer
D. O 2 2- < O 2 - < O 2 < O 2 +
Step-by-step solution
Bond order = number   of   bonding   e - - number   of   antibonding   e - 2 Electronic configuration of O 2 ,   O 2 + ,   O 2 -   and   O 2 - 2 are: O 2 = σ 1 s 2 σ 1 s 2 * σ 2 s 2 σ 2 s 2 * σ 2 p x 2 π 2 p y 2 = π 2 p z 2 π 2 p y 1 * = π 2 p z 1 *   ( Bond   order = 2 ) O 2 + = σ 1 s 2 σ 1 s 2 * σ 2 s 2 σ 2 s 2 * σ 2 p x 2 π 2 p y 2 = π 2 p z 2 π 2 p y 1 * = π 2 p z