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The correct order of bond orders of C 2 2 - , N 2 2 - and O 2 2 - is

Options

  1. AC 2 2 - > N 2 2 - > O 2 2 -
  2. BO 2 2 - > N 2 2 - > O 2 2 -
  3. CN 2 2 - > O 2 2 - > C 2 2 -
  4. DC 2 2 - > O 2 2 - > N 2 2 -

Correct answer

A. C 2 2 - > N 2 2 - > O 2 2 -

Step-by-step solution

Bond order = N b - N a 2 N B = Number of electrons in bonding molecular orbitals. N A · B = Number of electrons in anti bonding molecular orbitals. C 2 2 - has 14 electrons, it is isoelectronic with N 2 where Bond order = 3 , N 2 2 - has 16 electrons is isoelectronic with O 2 whose bond order = 2 O 2 2 - has 18 electrons and is isoelectronic with F 2 whose bond order = 1 So, the correct order of Bond order is C 2 2 - > N 2 2 - > O 2 2 - .

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