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JEE Main20211 Sep 2021Evening ShiftChemistryChemical Bonding and Molecular StructureActual

The spin-only magnetic moment value of B 2 + species is × 10 - 2 BM (Nearest integer) [ Given : 3 = 1 . 73 ]

Correct answer

0

Step-by-step solution

 In  B 2 number of electron  + = 9 B 2 = + ( σ 1   s ) 2 σ * 1   s 2 ( σ 2   s ) 2 σ ⋆ 2   s 2 π 2 p x = 1 π 2 p y 0 , so unpaired electron = 1 μ = n ( n + 2 ) B μ = 3     B.M.  = 1 . 73 = 173 × 10 - 2  B.M 

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