JEE Main202126 Feb 2021Evening ShiftChemistryChemical Bonding and Molecular StructureActual
Match List- I with List- II . List- I List- II (Molecule) (Bond order) (a) Ne 2 (i) 1 (b) N 2 (ii) 2 (c) F 2 (iii) 0 (d) O 2 (iv) 3 Choose the correct answer from the options given below:
Options
- Aa → ii ,   b → i ,   c → iv ,   d → iii
- Ba → iii ,   b → iv ,   c → i ,   d → ii
- Ca → i ,   b → ii ,   c → iii ,   d → iv
- Da → iv ,   b → iii ,   c → ii ,   d → i
Correct answer
B. a → iii ,   b → iv ,   c → i ,   d → ii
Step-by-step solution
Bond order = 1 2 ​ (number of electrons in bonding MO - number of electrons in anti-bonding MO) (a) Ne 2 = Total e Θ = 20 B.O. = 10 - 10 2 = 0 (b) N 2 = Total e ⊝ = 14 B.O. = 10 - 4 2 = 3 (c) F 2 = Total e ⊝ = 18 B.O. = 10 - 8 2 = 1 (d) O 2 = Total e ⊝ = 16 B.O. = 10 - 6 2 = 2