Match List- I with List- II . List- I List- II (Molecule) (Bond order) (a) Ne _ 2 (i) 1 (b) N _ 2 (ii) 2 (c) F _ 2 (iii) 0 (d) O _ 2 (iv) 3 Choose the correct answer from the options given below:

JEE Main 202126 FebruaryEvening Shift

JEE Main 2021 · 26 February · Evening Shift · Chemistry · Chemical Bonding and Molecular Structure

Match List- I with List- II . List- I List- II (Molecule) (Bond...

Match List- $I$ with List- $II$ .

Choose the correct answer from the options given below:

A $\left(a\right) \to \left(ii\right), \left(b\right) \to \left(i\right), \left(c\right) \to \left(iv\right), \left(d\right) \to \left(iii\right)$
B $\left(a\right) \to \left(iii\right), \left(b\right) \to \left(iv\right), \left(c\right) \to \left(i\right), \left(d\right) \to \left(ii\right)$
C $\left(a\right) \to \left(i\right), \left(b\right) \to \left(ii\right), \left(c\right) \to \left(iii\right), \left(d\right) \to \left(iv\right)$
D $\left(a\right) \to \left(iv\right), \left(b\right) \to \left(iii\right), \left(c\right) \to \left(ii\right), \left(d\right) \to \left(i\right)$

B. $\left(a\right) \to \left(iii\right), \left(b\right) \to \left(iv\right), \left(c\right) \to \left(i\right), \left(d\right) \to \left(ii\right)$

Bond order = $\dfrac{1}{2}$ â€‹ (number of electrons in bonding MO $-$ number of electrons in anti-bonding MO)

(a) ${Ne}_{2} =$ Total ${e}^{Θ} = 20$

B.O. $= \dfrac{10 - 10}{2} = 0$

(b) ${N}_{2} =$ Total ${e}^{⊝} = 14$

B.O. $= \dfrac{10 - 4}{2} = 3$

B.O. $= \dfrac{10 - 8}{2} = 1$

(d) ${O}_{2} =$ Total ${e}^{⊝} = 16$

B.O. $= \dfrac{10 - 6}{2} = 2$