If the magnetic moment of a di-oxygen species is 1.73 B . M . , it may be

Step-by-step solution

Given, magnetic moment of di-oxygen species = 1 . 73   B . M . We know, magnetic moment = n n + 2 , where n = number of unpaired electrons 1.73 = n n + 2 n = 1 So, species should contain one unpaired electron. Let us check by electronic configuration of each species O 2 = σ 1 s 2   σ * 1 s 2   σ 2 s 2   σ * 2 s 2   σ 2 p 2 z   π 2 p 2 x = π 2 p 2 y   π * 2 p 1 x = π * 2 p 1 y O 2 + = σ 1 s 2   σ * 1 s 2   σ 2 s