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JEE Main201910 Jan 2019Morning ShiftChemistryChemical Bonding and Molecular StructureActual

The type of hybridization and no. of lone pair(s) of electron of X e in X e O F 4 , respectively, are:

Options

  1. As p 3 d 2 and 1
  2. Bs p 3 d 2 and 2
  3. Cs p 3 d and 2
  4. Ds p 3 d and 1

Correct answer

A. s p 3 d 2 and 1

Step-by-step solution

Steric no. = 6 , hybridisation = s p 3 d 2 No. of lone pairs on X e = 1

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