In graphite and diamond, the percentage of p-characters of the hybrid orbitals in hybridization respectively, are

Step-by-step solution

Graphite Diamond sp 2 hybridisation sp 3 hybridisation %  P = 2 3 × 100 = 67 % %  P = 3 4 × 100 = 75 % For sp 2 : % P character P − 1 P = cosθ P − 1 P = cos 120 = − 0 .5 P − 1 = 0 .5 P 1 .5 P = 1 P = 2 3 % P = 2 3 × 100 = 66 .67 % For sp 3 : % P character P − 1 P = cos 109 ' 28 P − 1 P = 0 .33 P − 1 P = 3 4 % P = 75 %