JEE Main2014ChemistryChemical Bonding and Molecular StructureActual
The correct order of bond dissociation energy among N ₂, O ₂, O ₂⁻ is shown in which of the following arrangements?
Options
- AN ₂> O ₂⁻> O ₂
- BO ₂⁻> O ₂> N ₂
- CN ₂> O ₂> O ₂⁻
- DO ₂> O ₂⁻> N ₂
Correct answer
C. N ₂> O ₂> O ₂⁻
Step-by-step solution
The bond order of N ₂, O ₂ , and O ₂⁻ are respectively 3,2 and 1.5 Since higher bond order implies higher bond dissociation energy hence the correct order will be N ₂> O ₂> O ₂⁻