Bond distance in HF is 9.17 10⁻¹¹ ~m . Dipole moment of HF is 6.104 10⁻³⁰ Cm . The percentage ionic character in HF will be : (electron charge =1.60 10⁻¹⁹ C )

Step-by-step solution

Given e=1.60 10⁻¹⁹ C d=9.17 10⁻¹¹ ~m From =e d aligned & =1.60 10⁻¹⁹ 9.17 10⁻¹¹ & =14.672 10⁻³⁰ aligned % ionic character = Observed dipole moment Dipole moment for 100 % aligned & = 6.104 10⁻³⁰ 14.672 10⁻³⁰ 100 & =41.5 % aligned