The value of K _ c us64at800K for the reaction N _ 2 (g) + 3 H _ 2 (g) → 2 NH _ 3 (g) The value of K _ c for the following reaction is : NH _ 3 (g) → (1)/(2) N _ 2 (g) + (3)/(2) H _ 2 ( g )

Correct answer: D. 1 / 8 N _ 2 (g) + 3 H _ 2 (g) ⇌ 2 NH _ 3 (g) K _ C = [ NH _ 3 ] ^ 2 [ N _ 2 ] [ H _ 2 ] ^ 3 = 64 For the reaction NH _ 3 (g) ⇌ (1)/(2) N _ 2 (g) + (3)/(2) H _ 2 (g) K ' _ C = [ N _ 2 ] ^ 1 / 2 [ H _ 2 ] ^ 3 / 2 [ NH _ 3 ] = 1 K _ C = 1 64 = (1)/(8)

JEE Main 20206 SeptemberEvening Shift

Exam: JEE Main
Year: 2020
Date: 6 September
Shift: Evening Shift
Subject: Chemistry
Chapter: Chemical Equilibrium

JEE Main 2020 · 6 September · Evening Shift · Chemistry · Chemical Equilibrium

The value of K _ c us64at800K for the reaction N _ 2 (g) + 3 H _ 2...

The value of ${K}_{c}us64at800K$ for the reaction

${N}_{2}\left(g\right) + 3{H}_{2}\left(g\right) \to 2{NH}_{3}\left(g\right)$

The value of ${K}_{c}$ for the following reaction is :

${NH}_{3}\left(g\right) \to \dfrac{1}{2}{N}_{2}\left(g\right) + \dfrac{3}{2}{H}_{2} ( g )$

Options

A $1 / 64$
B $8$
C $1 / 4$
D $1 / 8$

Correct answer

D. $1 / 8$

Step-by-step solution

${N}_{2}\left(g\right) + 3{H}_{2}\left(g\right) ⇌ 2{NH}_{3}\left(g\right)$

${K}_{C} = \dfrac{{\left[{NH}_{3}\right]}^{2}}{\left[{N}_{2}\right]{\left[{H}_{2}\right]}^{3}} = 64$

For the reaction

${NH}_{3}\left(g\right) ⇌ \dfrac{1}{2}{N}_{2}\left(g\right) + \dfrac{3}{2}{H}_{2}\left(g\right)$

$K{'}_{C} = \dfrac{{\left[{N}_{2}\right]}^{1 / 2}{\left[{H}_{2}\right]}^{3 / 2}}{\left[{NH}_{3}\right]} = \dfrac{1}{\sqrt{{K}_{C}}} = \dfrac{1}{\sqrt{64}} = \dfrac{1}{8}$

Practice Chemical Equilibrium on Quantrex Academy →

More from Chemical Equilibrium

Consider the following reactions in which all the reactants and products are present in… JEE Main 2026 Solid carbon, CaO and CaCO _3 are mixed and allowed to attain equilibrium at T K.… JEE Main 2026 In a closed flask at 600 K, one mole of X _2 Y _4 (g) attains equilibrium as given below… JEE Main 2026 One mole each of He and A(g) are taken in a 10 L closed flask and heated to 400 K to… JEE Main 2026 The reaction A(g) leftharpoons B(g) + C(g) was initiated with the amount ' a ' of A(g) .… JEE Main 2026 The values of pressure equilibrium constant recorded at different temperatures for the… JEE Main 2026 For the following reaction at 50° C and at 2 atm pressure, 2N_2O_5(g) leftharpoons… JEE Main 2026 At T(K) , the equilibrium constant of A_2(g) + B_2(g) leftharpoons C(g) is 2.7 × 10^ -5 .… JEE Main 2026 Full Chemical Equilibrium list All JEE Main PYQs