JEE Main20266 April 2026Evening ShiftChemistryChemical KineticsActual
Decomposition of a hydrocarbon follows the equation k = (5.5 10¹¹ , s ⁻¹) ,e^ -28000 , K T . The activation energy of reaction is __________ kJ mol ⁻¹ . (Nearest Integer) Given : R = 8.3 J K ⁻¹ mol ⁻¹
Correct answer
0
Step-by-step solution
According to the Arrhenius equation, k = A e^ - E_a RT . The given equation is k = (5.5 10¹¹ s ⁻¹) e^ - 28000 T . Comparing the exponent of e in both equations: E_a RT = 28000 T E_a = 28000 R Substituting the value of R = 8.3 J K ⁻¹ mol ⁻¹ : E_a = 28000 8.3 J mol ⁻¹ E_a = 232400 J mol ⁻¹ E_a = 232.4 kJ mol ⁻¹ Rounding to the nearest integer, the activation energy is 232 . Answer: 232