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JEE Main 202522 JanuaryMorning Shift
Exam
JEE Main
Year
2025
Date
22 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Electrochemistry

JEE Main 2025 · 22 January · Morning Shift · Chemistry · Electrochemistry

A solution of aluminium chloride is electrolysed for 30 minutes...

A solution of aluminium chloride is electrolysed for 30 minutes using a current of 2 A . The amount of the aluminium deposited at the cathode is [Given : molar mass of aluminium and chlorine are 27 g mol−127 \mathrm{~g} \mathrm{~mol}^{-1} and 35.5 g mol−135.5 \mathrm{~g} \mathrm{~mol}^{-1} respectively. Faraday constant =96500Cmol−1]\left.=96500 \mathrm{C} \mathrm{mol}^{-1}\right]

Options

  1. A1.660 g
  2. B0.336 g
  3. C0.441 g
  4. D1.007 g

Correct answer

B. 0.336 g

Step-by-step solution

Al1+++3e−⟶Al\mathrm{Al}^{1++}+3 \mathrm{e}^{-} \longrightarrow \mathrm{Al} Moles of electron =2×30×6096500=36965\begin{aligned} \text{ Moles of electron } & =\frac{2 \times 30 \times 60}{96500} \\ & =\frac{36}{965} \end{aligned} Moles of Al=363×965=12965\begin{aligned} \text{ Moles of } \mathrm{Al} & =\frac{36}{3 \times 965} \\ & =\frac{12}{965} \end{aligned}\text{ Mass of } Al=12965×27=0.336gm\mathrm{Al}=\frac{12}{965} \times 27 =0.336 \mathrm{gm}
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