JEE Advanced2024ChemistryElectrochemistryActual
An aqueous solution of hydrazine ( N ₂ H ₄ ) is electrochemically oxidized by O ₂ , thereby releasing chemical energy in the form of electrical energy. One of the products generated from the electrochemical reaction is N ₂( ~g ) . Choose the correct statement(s) about the above process :
Options
- AOH ⁻ ions react with N ₂ H ₄ at the anode to form N ₂( ~g ) and water, releasing 4 electrons to the anode.
- BAt the cathode, N ₂ H ₄ breaks to N ₂( ~g ) and nascent hydrogen released at the electrode reacts with oxygen
- CAt the cathode, molecular oxygen gets converted to OH ⁻ .
- DOxides of nitrogen are major by-products of the electrochemical process.
Correct answer
A. OH ⁻ ions react with N ₂ H ₄ at the anode to form N ₂( ~g ) and water, releasing 4 electrons to the anode.
Step-by-step solution
( Oxidation (Anode) -2 N₂H₄ + Reduction (Cathode) 0 O₂ 0 N₂ + H ₂ O ⁻² ) At anode: ( N ₂ H ₄+4 OH ⁻ N ₂+4 H ₂ O +4 e⁻ ) At cathode: ( O ₂+2 H ₂ O +4 e⁻ 4 OH ⁻ ) Complete reaction: ( N ₂ H ₄+ O ₂ N ₂+2 H ₂ O ) Statements (A) and (C) are correct.