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JEE Main 20249 AprilMorning Shift
Exam
JEE Main
Year
2024
Date
9 April
Shift
Morning Shift
Subject
Chemistry
Chapter
Electrochemistry

JEE Main 2024 · 9 April · Morning Shift · Chemistry · Electrochemistry

The standard reduction potentials at (298 ~K) for the following...

The standard reduction potentials at (298 \mathrm{~K}) for the following half cells are given below : (Cr2O72−+14H++6e−→2Cr3++7H2O,E∘=1.33 VFe3+(aq)+3e−→FeE∘=−0.04 VNi2+(aq)+2e−→NiE∘=−0.25 VAg+(aq)+e−→AgE∘=0.80 VAu3+(aq)+3e−→AuE∘=1.40 V\begin{array}{ll} \mathrm{Cr}_2 \mathrm{O}_7^{2-}+14 \mathrm{H}^{+}+6 \mathrm{e}^{-} \rightarrow 2 \mathrm{Cr}^{3+}+7 \mathrm{H}_2 \mathrm{O}, \mathrm{E}^{\circ}=1.33 \mathrm{~V} \\ \mathrm{Fe}^{3+}(\mathrm{aq})+3 \mathrm{e}^{-} \rightarrow \mathrm{Fe} \qquad \mathrm{E}^{\circ}=-0.04 \mathrm{~V} \\ \mathrm{Ni}^{2+}(\mathrm{aq})+2 \mathrm{e}^{-} \rightarrow \mathrm{Ni} \qquad \mathrm{E}^{\circ}=-0.25 \mathrm{~V} \\ \mathrm{Ag}^{+}(\mathrm{aq})+\mathrm{e}^{-} \rightarrow \mathrm{Ag} \quad\qquad \mathrm{E}^{\circ}=0.80 \mathrm{~V} \\ \mathrm{Au}^{3+}(\mathrm{aq})+3 \mathrm{e}^{-} \rightarrow \mathrm{Au} \qquad \mathrm{E}^{\circ}=1.40 \mathrm{~V} \end{array}) Consider the given electrochemical reactions, The number of metal(s) which will be oxidized be (\mathrm{Cr}_2 \mathrm{O}_7^{2-}), in aqueous solution is ______

Correct answer

0

Step-by-step solution

Fe,Ni,Ag\mathrm{Fe}, \mathrm{Ni}, \mathrm{Ag} will be oxidized due to lower S.R.P.
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