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JEE Main 20248 AprilEvening Shift
Exam
JEE Main
Year
2024
Date
8 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Electrochemistry

JEE Main 2024 · 8 April · Evening Shift · Chemistry · Electrochemistry

The emf of cell Tl (| (0.001 M) Tl^ + || (0.01 M) Cu^ 2+ | Cu) is...

The emf of cell Tl (\left|\underset{(0.001 \mathrm{M})}{\mathrm{Tl}^{+}}\right|\left|\underset{(0.01 \mathrm{M})}{\mathrm{Cu}^{2+}}\right| \mathrm{Cu}) is (0.83 \mathrm{~V}) at (298 \mathrm{~K}). It could be increased by :

Options

  1. Adecreasing concentration of both (\mathrm{Tl}^{+}) and (\mathrm{Cu}^{2+}) ions
  2. Bincreasing concentration of (\mathrm{Cu}^{2+}) ions
  3. Cincreasing concentration of (\mathrm{T1}^{+})ions
  4. Dincreasing concentration of both (\mathrm{Tl}^{+}) and (\mathrm{Cu}^{2+}) ions

Correct answer

B. increasing concentration of (\mathrm{Cu}^{2+}) ions

Step-by-step solution

Anodic Reaction{\left[T \ell_{(s)} \rightarrow T^{+}{ }_{(aq)}+e^{-}\right] 2}
Cathodic ReactionCu^{+2}{ }_{(aq)}+2 e^{-} \rightarrow Cu_{(s)}
Overall Redox Reaction2 T \ell_{(s)}+Cu^{+2}{ }_{(aq)} \rightarrow 2 T \ell_{(aq)}^{+}+Cu_{(s)}
\mathrm{E}_{\text{cell }}=\mathrm{E}_{\text{cell }}^o-\frac{0.0591}{2} \log \frac{\left[\mathrm{T} \ell^{+}\right]^2}{\left[\mathrm{Cu}^{+2}\right]} \mathrm{E}_{\text{cell }}increasesbyincreasingconcentrationof[Cu+2]increases by increasing concentration of \left[\mathrm{Cu}^{+2}\right] ions.
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