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JEE Main 20241 FebruaryEvening Shift

Exam: JEE Main
Year: 2024
Date: 1 February
Shift: Evening Shift
Subject: Chemistry
Chapter: Electrochemistry

JEE Main 2024 · 1 February · Evening Shift · Chemistry · Electrochemistry

The amount of electricity in Coulomb required for the oxidation of...

The amount of electricity in Coulomb required for the oxidation of

1mol

of

{H}_{2}O

to

{O}_{2}

is ______

\times {10}^{5}C .

Correct answer

0

Step-by-step solution

${H}_{2}O \to \dfrac{1}{2}{O}_{2} + 2{H}^{+} + 2{e}^{-}$

Electricity required to oxidise $1$ mol ${H}_{2}O\text{to}{O}_{2} = 2F$

$\dfrac{W}{E} = \dfrac{Q}{96500}$

mole $\times n$ -factor $= \dfrac{Q}{96500}$

$1 \times 2 = \dfrac{Q}{96500}$

$Q = 2 \times 96500C$

$= 1 . 93 \times {10}^{5}C$

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