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JEE Main 202431 JanuaryMorning Shift
Exam
JEE Main
Year
2024
Date
31 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Electrochemistry

JEE Main 2024 · 31 January · Morning Shift · Chemistry · Electrochemistry

One Faraday of electricity liberates x × 10 ^ – 1 gram atom of...

One Faraday of electricity liberates x×10–1x \times {10}^{– 1} gram atom of copper from copper sulphate, xx is______.

Correct answer

0

Step-by-step solution

One Faraday of electricity means it is equivalent to one mole of electrons charge.

Cu2++2e–→Cu{Cu}^{2 +} + 2{e}^{–} \to Cu

22 Faraday →1molCu\to 1molCu

11 Faraday →0.5molCu\to 0 . 5molCu deposit

0.5mol=0.5gatom=5×10–10 . 5mol = 0 . 5gatom = 5 \times {10}^{– 1}

x=5x = 5

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