The mass of zinc produced by the electrolysis of zinc sulphate solution with a steady current of 0 . 015 A for 15 minutes is _ _ _ _ × 10 - 4 g . (Atomic mass of zinc = 65 . 4 amu )

Step-by-step solution

Given, t = 15 min Zn + 2 + 2 e - ⟶ Zn Quantity of charge passed (Q) =Current in amperes ×Time in seconds. = ( 0 . 015 A ) × ( 15 × 60 ) s = 13 . 5 C Gram equivalent mass of zinc = 65 . 4 2 = 32 . 7 g Now, 96500 C of charge deposit zinc = 32 . 7 g 13 . 5 C charge will deposit zinc = ( 32 . 7 g ) ( 96500 C ) × ( 13 . 5 C ) = 4 . 57 × 10 − 3 g = 45 . 75 × 10 - 4 gm