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JEE Main 202331 JanuaryEvening Shift
Exam
JEE Main
Year
2023
Date
31 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Electrochemistry

JEE Main 2023 · 31 January · Evening Shift · Chemistry · Electrochemistry

The resistivity of a 0 . 8M solution of an electrolyte is 5 × 10 ^...

The resistivity of a 0.8M0 . 8M solution of an electrolyte is 5×10−3Ωcm5 \times {10}^{- 3}Ωcm. Its molar conductivity is 104Ω−1cm2mol−1{10}^{4}{Ω}^{- 1}{cm}^{2}{mol}^{- 1}. (Nearest integer)

Correct answer

0

Step-by-step solution

Given,
Resistivity (ρ)=5×10−3Ωcm( ρ ) = 5 \times {10}^{- 3}Ωcm

Molarity (M)=0.8M( M ) = 0 . 8M

Thus, Molar conductivity of electrolyte \left({\lambda}_{M}\right) = \dfrac{1}{ρ} \times \dfrac{1000}{M}</p><p></p><p>= \dfrac{1}{5 \times {10}^{- 3}} \times \dfrac{1000}{0 . 8}</p><p></p><p>= 0 . 25 \times {10}^{6}</p><p></p><p>= 25 \times {10}^{4}{cm}^{2}{mol}^{- 1}$.

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