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JEE Main 202228 JulyMorning Shift
Exam
JEE Main
Year
2022
Date
28 July
Shift
Morning Shift
Subject
Chemistry
Chapter
Electrochemistry

JEE Main 2022 · 28 July · Morning Shift · Chemistry · Electrochemistry

Match List-I with List-II. List-I List-II A Cd(s) + 2Ni (OH) _ 3...

Match List-I with List-II.

List-I List-II
A Cd(s)+2Ni(OH)3(s)→CdO(s)+2Ni(OH)2(s)+H2O(l)Cd\left(s\right) + 2Ni{\left(OH\right)}_{3}\left(s\right) \to CdO\left(s\right) + 2Ni{\left(OH\right)}_{2}\left(s\right) + {H}_{2}O\left(l\right) I Primary battery
B Zn(Hg)+HgO(s)→ZnO(s)+Hg(l)Zn\left(Hg\right) + HgO\left(s\right) \to ZnO\left(s\right) + Hg\left(l\right) II Discharging of secondary battery
C 2PbSO4(s)+2H2O(I)→Pb(s)+PbO2(s)+2H2SO4(aq)2{PbSO}_{4}\left(s\right) + 2{H}_{2}O\left(I\right) \to Pb\left(s\right) + {PbO}_{2}\left(s\right) + 2{H}_{2}{SO}_{4}\left(aq\right) III Fuel cell
D 2H2(g)+O2(g)→2H2O(l)2{H}_{2}\left(g\right) + {O}_{2}\left(g\right) \to 2{H}_{2}O\left(l\right) IV Charging of secondary battery

Choose the correct answer from the options given below

Options

  1. AA−I,B−II,C−III,C−IVA - I, B - II, C - III, C - IV
  2. BA−IV,B−I,C−IV,C−IIIA - IV, B - I, C - IV, C - III
  3. CA−II,B−I,C−IV,C−IIIA - II, B - I, C - IV, C - III
  4. DA−II,B−I,C−III,C−IVA - II, B - I, C - III, C - IV

Correct answer

C. A−II,B−I,C−IV,C−IIIA - II, B - I, C - IV, C - III

Step-by-step solution

(a)Cd(s)+2Ni(OH)3(s)→CdO(s)+2Ni(OH)2(s)+H2O(l)Cd\left(s\right) + 2Ni{\left(OH\right)}_{3}\left(s\right) \to CdO\left(s\right) + 2Ni{\left(OH\right)}_{2}\left(s\right) + {H}_{2}O\left(l\right)
Discharge of secondary Battery

(b)Zn(Hg)+HgO(s)→ZnO(s)+Hg(l)Zn\left(Hg\right) + HgO\left(s\right) \to ZnO\left(s\right) + Hg\left(l\right)
(Primary Battery Mercury cell)

(c) 2PbSO4(s)+2H2O(l)→Pb(s)+PbO2(s)+2H2SO4(aq)2{PbSO}_{4}\left(s\right) + 2{H}_{2}O\left(l\right) \to Pb\left(s\right) + {PbO}_{2}\left(s\right) + 2{H}_{2}{SO}_{4}\left(aq\right) Charging of secondary Battery

(d) 2H2(g)+O2(g)→2H2O(l)−2{H}_{2}\left(g\right) + {O}_{2}\left(g\right) \to 2{H}_{2}O\left(l\right) - Fuel cell

Mercury cell, suitable for low current devices like hearing aids, watches, etc. consists of zinc - mercury amalgam as anode and a paste of HgOHgO and carbon as the cathode. The electrolyte is a paste of KOHKOH and ZnOZnO. The electrode reactions for the cell are given below:

Anode: Zn(Hg)+2OH−→ZnO(s)+H2O+2e−Zn\left(Hg\right) + 2{OH}^{-} \to ZnO\left(s\right) + {H}_{2}O + 2{e}^{-}

Cathode: HgO+H2O+2e−→Hg(l)+2OH−HgO + {H}_{2}O + 2{e}^{-} \to Hg\left(l\right) + 2{OH}^{-}

Another important secondary cell is the nickel-cadmium cell which has longer life than the lead storage cell but more expensive to manufacture.

The overall reaction during discharge is:

Cd(s)+2Ni(OH)3(s)→CdO(s)+2Ni(OH)2(s)+H2O(l)Cd\left(s\right) + 2Ni{\left(OH\right)}_{3}\left(s\right) \to CdO\left(s\right) + 2Ni{\left(OH\right)}_{2}\left(s\right) + {H}_{2}O\left(l\right)

Fuel cell using H2{H}_{2} and O2{O}_{2} produces electricity.

Cathode: O2(g)+2H2O(l)+4e−→4OH−(aq){O}_{2}\left(g\right) + 2{H}_{2}O\left(l\right) + 4{e}^{-} \to 4{OH}^{-}\left(aq\right)

Anode: 2H2(g)+4OH−(aq)→4H2O(l)+4e−2{H}_{2}\left(g\right) + 4{OH}^{-}\left(aq\right) \to 4{H}_{2}O\left(l\right) + 4{e}^{-}

Overall reaction being:

2H2(g)+O2(g)→2H2O(l)2{H}_{2}\left(g\right) + {O}_{2}\left(g\right) \to 2{H}_{2}O\left(l\right)

(ii) Cell reaction of lead storage battery during recharge -

The reverse of oxidation at anode during discharge is the reduction reaction at cathode during recharging.

Pb(aq)2++2e−→Pb(s){Pb}_{\left(aq\right)}^{2 +} + 2{e}^{-} \to {Pb}_{\left(s\right)}

PbSO4(s)→Pb(aq)2++SO4(aq)2−{PbSO}_{4\left(s\right)} \to {Pb}_{\left(aq\right)}^{2 +} + {SO}_{4\left(aq\right)}^{2 -}

Final Reaction: PbSO4(s)+2e−→Pb(s)+SO4(aq)2−{PbSO}_{4\left(s\right)} + 2{e}^{-} \to {Pb}_{\left(s\right)} + {SO}_{4\left(aq\right)}^{2 -}

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