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The quantity of electricity in Faraday needed to reduce 1 mol of Cr 2 O 7 2 - to Cr 3 + is

Correct answer

6

Step-by-step solution

1 faraday of charge is the magnitude of charge of one mole of electrons. According to the given reaction: C r 2 O 7 2 - +   6 e - ⟶ 2 C r 3 + Reduction of 1   mol of C r 2 O 7 2 - to C r 3 + requires 6 moles of electrons. Hence, charge required = 6   Faraday

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