The correct order of reduction potentials of the following pairs is
A. ${Cl}_{2} / {Cl}^{-}$
B. ${I}_{2} / {I}^{-}$
C. ${Ag}^{+} / Ag$
D. ${Na}^{+} / Na$
E. ${Li}^{+} / Li$
Choose the correct answer from the options given below.

Question

The correct order of reduction potentials of the following pairs is

A. ${Cl}_{2} / {Cl}^{-}$

B. ${I}_{2} / {I}^{-}$

C. ${Ag}^{+} / Ag$

D. ${Na}^{+} / Na$

E. ${Li}^{+} / Li$

Choose the correct answer from the options given below.

Quantrex Academy · Accepted Answer

Correct answer: D. A > C > B > D > E

array ll E _ Cl _ 2 ∣ Cl ^ - ^ 0 = 1 .36 E ^ ∘ I _ 2 ∣ I ^ - = 0 .54 E _ Li ^ + | Li = - 3 .05 E ^ ∘ Ag ^ + ∣ Ag = 0 .80 E _ Na ^ + | Na = - 2 .71 array So, we can clearly see the order of reduction potential. A > C > B > D > E

The correct order of reduction potentials of the following pairs is...

Options

Correct answer

Step-by-step solution

More from Electrochemistry