JEE Main202225 Jun 2022Evening ShiftChemistryElectrochemistryActual
A solution of Fe 2 SO 4 3 is electrolyzed for ' x ' min with a current of 1 . 5   A to deposit 0 . 3482   g of Fe . The value of x is - [nearest integer] Given : 1   F = 96500   Cmol - 1 . Atomic mass of Fe = 56   gmol - 1
Correct answer
0
Step-by-step solution
Fe 2 SO 4 3 ⟶ 2 Fe w = Zit w = E 96500 it 0 . 3482 = 56 3 × 96500 × 1 . 5 × t t = 1200   sec = 20   min