A solution of Fe _ 2 ( SO _ 4 ) _ 3 is electrolyzed for ' x ' min...

A solution of ${Fe}_{2}{\left({SO}_{4}\right)}_{3}$ is electrolyzed for ' $x$ ' min with a current of $1 . 5A$ to deposit $0 . 3482g$ of $Fe$ . The value of $x$ is - [nearest integer]

Given : $1F = 96500{Cmol}^{- 1}$ . Atomic mass of $Fe = 56{gmol}^{- 1}$

Correct answer

Step-by-step solution

${Fe}_{2}{\left({SO}_{4}\right)}_{3} ⟶ 2Fe$

$w = Zit$

$w = \left(\dfrac{E}{96500}\right)$ it

$0 . 3482 = \left(\dfrac{56}{3 \times 96500}\right) \times 1 . 5 \times t$

$t = 1200sec = 20min$

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