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JEE Main 20211 SeptemberEvening Shift
Exam
JEE Main
Year
2021
Date
1 September
Shift
Evening Shift
Subject
Chemistry
Chapter
Electrochemistry

JEE Main 2021 · 1 September · Evening Shift · Chemistry · Electrochemistry

If the conductivity of mercury at 0 ° C is 1 . 07 × 10 ^ 6 S m ^ -...

If the conductivity of mercury at 0°C0 ° C is 1.07×106Sm−11 . 07 \times {10}^{6}S{m}^{- 1} and the resistance of a cell containing mercury is 0.243Ω,0 . 243Ω, then the cell constant of the cell is x×104m−1.x \times {10}^{4}{m}^{- 1} . The value of xx is ______ . (Nearest integer)

Correct answer

0

Step-by-step solution

k=1.07×106Sm−1,R=0.243Ωk = 1 . 07 \times {10}^{6}{Sm}^{- 1}, R = 0 . 243Ω

G=1R=10.243Ω−1G = \dfrac{1}{R} = \dfrac{1}{0 . 243}{Ω}^{- 1}

k=G×G∗k = G \times {G}^{*}

G∗=kG=1.07×10610.243=26×104m−1{G}^{*} = \dfrac{k}{G} = \dfrac{1 . 07 \times {10}^{6}}{\dfrac{1}{0 . 243}} = 26 \times {10}^{4}{m}^{- 1}

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