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JEE Main202131 Aug 2021Evening ShiftChemistryElectrochemistryActual

Match List - I with List - II : List - I (Parameter) List - II (Unit) (a) Cell constant (i) S cm 2 mol - 1 (b) Molar conductivity (ii) Dimensionless (c) Conductivity (iii) m - 1 (d) Degree of dissociation of electrolyte (iv) Ω - 1 m - 1

Options

  1. A(a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
  2. B(a)-(iii), (b)-(i), (c)-(ii), (d)-(iv)
  3. C(a)-(iii), (b)-(iv), (c)-(i), (d)-(ii)
  4. D(a)-(ii), (b)-(i), (c)-(iii), (d)-(iv)

Correct answer

A. (a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)

Step-by-step solution

Cell constant = ℓ A = m - 1 Conductivity k = 1 ρ = ℓ RA = Ω - 1   m - 1 Molar Conductivity = λ m = k × 1000  Molarity  = S   cm 2   mol - 1 Degree of dissociation = Number of mole dissociated out of one mole, hence, it is dimensionless.

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