A KCl solution of conductivity 0 . 14S m ^ - 1 shows a resistance...

The thermal conductivity of a material is a measure of its ability to conduct heat. It is commonly denoted by $κ$, \lambda, or \kappa. Heat transfer occurs at a lower rate in materials of low thermal conductivity than in materials of high thermal conductivity

$κ = \dfrac{1}{R} \cdot {G}^{*}$

For same conductivity cell, ${G}^{*}$ is constant and hence $κ \cdot R . =$ constant.

$∴ 0 . 14 \times 4 . 19 = κ \times 1 . 03$

or, $= \dfrac{0 . 14 \times 4 . 19}{1 . 03}$

$= 0 . 5695{Sm}^{- 1}$

$= 56 . 95 \times {10}^{- 2}{Sm}^{- 1} \approx 57 \times {10}^{- 2}{Sm}^{- 1}$