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JEE Main 202118 MarchMorning Shift
Exam
JEE Main
Year
2021
Date
18 March
Shift
Morning Shift
Subject
Chemistry
Chapter
Electrochemistry

JEE Main 2021 · 18 March · Morning Shift · Chemistry · Electrochemistry

For the reaction 2 Fe ^ 3 + ( aq ) + 2 I ^ - ( aq ) → 2 Fe ^ 2 + (...

For the reaction
2Fe3+(aq)+2I−(aq)→2Fe2+(aq)+I2(s)2{Fe}^{3 +} ( aq ) + 2{I}^{-} ( aq ) \to 2{Fe}^{2 +} ( aq ) + {I}_{2} ( s )
the magnitude of the standard molar free energy change, ∆rGm∘=−{∆}_{r}{G}_{m}^{∘} = -______kJkJ (Round off to the Nearest Integer).

For the reaction 2 Fe ^ 3 + ( aq ) + 2 I ^ - ( aq ) → 2 Fe ^ 2 + ( aq ) + I _ 2 ( s ) the magnitude of the standard

Correct answer

0

Step-by-step solution

Standard electrode potential is a measurement of the potential for equilibrium. There is a potential difference between the electrode and the electrolyte called the potential of the electrode. When unity is the concentrations of all the species involved in a semi-cell, the electrode potential is known as the standard electrode potential.

For the reaction 2 Fe ^ 3 + ( aq ) + 2 I ^ - ( aq ) → 2 Fe ^ 2 + ( aq ) + I _ 2 ( s ) the magnitude of the standard

E10+2E20=3E30{E}_{1}^{0} + 2{E}_{2}^{0} = 3{E}_{3}^{0}
E10=3E30−2E20{E}_{1}^{0} = 3{E}_{3}^{0} - 2{E}_{2}^{0}

=3(−0.036)−2(−0.44)= 3 ( - 0 . 036 ) - 2 ( - 0 . 44 )
=+0.772V= + 0 . 772V
Ecell0=EFe3+/Fe2+0+EI−/I20=0.233{E}_{\text{cell}}^{0} = {E}_{{Fe}^{3 +} / {Fe}^{2 +}}^{0} + {E}_{{I}^{-} / {I}_{2}}^{0} = 0 . 233
ΔrG0=−2×96.5×0.233=−45kJ{\Delta}_{r}{G}^{0} = - 2 \times 96 . 5 \times 0 . 233 = - 45kJ

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