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Potassium chlorate is prepared by the electrolysis of KCl in basic solution 6 OH - + Cl - → ClO 3 - + 3 H 2 O + 6 e - . If only 60 % of the current is utilized in the reaction, the time (rounded to the nearest hour) required to produce 10 g of KClO 3 using a current of 2 A is … … . . (Given : F = 96 , 500 C mol ; molar mass of KClO 3 = 122 g mol - 1 )

Correct answer

0

Step-by-step solution

Number of faradays = I × t 96500 = 2 × t × 60 × 60 96500 F Mass of KClO 3 produce = 10   Gm    2 × t × 60 × 60 / 96500 × 0 . 60 × 122 × ( 1 / 6 ) = 10 So t = 10 . 98 hours

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