When an electric current is passes through acidified water, 112 ~mL of hydrogen gas at N.T.P. was collected at the cathode in 965 seconds. The current passed, in ampere, is :

Step-by-step solution

Reduction at cathode: 2 e ⁻+2 H ₂ O H ₂+2 OH ⁻ (valence factor) H ₂=2 At NTP 22400 ~mL of H ₂=1 mole of H ₂ ~112 ~mL of H ₂= 1 22400 112=0.005 mole of H ₂ Moles of H ₂ produced aligned &= I t 96500 mole ratio &0.005= I 965 96500 1 mole of H ₂ 2 mole of e⁻ & I =1.0 ~A aligned