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JEE Main 201815 April
Exam
JEE Main
Year
2018
Date
15 April
Subject
Chemistry
Chapter
Electrochemistry

JEE Main 2018 · 15 April · Chemistry · Electrochemistry

When an electric current is passed through acidified water, 112 mL...

When an electric current is passed through acidified water, 112 mL of hydrogen gas at N.T.P was collected at the cathode in 965 seconds. The current passed, in ampere, is:

Options

  1. A2.0
  2. B0.1
  3. C0.5
  4. D1.0

Correct answer

D. 1.0

Step-by-step solution

Cathode
2e−+2H2O⟶H2+2OH−2{e}^{-} + 2{H}_{2}O ⟶ {H}_{2} + 2O{H}^{-} (v.f.)H2=2{\left(v . f .\right)}_{{H}_{2}} = 2
Mole =i×tv.f.×96500= \dfrac{i \times t}{v . f . \times 96500}
11222400=i×9652×96500\dfrac{112}{22400} = \dfrac{i \times 965}{2 \times 96500}
12=i2\dfrac{1}{2} = \dfrac{i}{2}
i=1ampi = 1amp

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