Consider the following standard electrode potentials ( E ^ o in volts) in aqueous solution: cases Element _ & M ^ 3 + / M _ & M ^ + / M _ Al & - 1.66 & + 0.55 Tl & + 1.26 & - 0.34 cases Based on these data, which of the

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JEE Main 2017 · 8 April · Online · Chemistry · Electrochemistry

Consider the following standard electrode potentials ( E ^ o in...

Consider the following standard electrode potentials (

{\text{E}}^{\text{o}}

in volts) in aqueous solution:

\begin{cases}\mathop{\text{E}\text{l}\text{e}\text{m}\text{e}\text{n}\text{t}}_{} & \mathop{{\text{M}}^{3 +} / \text{M}}_{} & \mathop{{\text{M}}^{+} / \text{M}}_{} \\ \text{A}\text{l} & - 1.66 & + 0.55 \\ \text{T}\text{l} & + 1.26 & - 0.34\end{cases}

Based on these data, which of the following statements is correct?

D. $\text{T}{\text{l}}^{+}$ is more stable than $\text{A}{\text{l}}^{+}$

∆ {\text{G}}^{\text{o}} = - \text{n}\text{F}{\text{E}}^{\text{o}}

{\text{E}}^{\text{o}} = \text{p}\text{o}\text{s}\text{i}\text{t}\text{i}\text{v}\text{e};

then

∆ {\text{G}}^{\text{o}} = \text{n}\text{e}\text{g}\text{a}\text{t}\text{i}\text{v}\text{e}

,

For those, conversions whose

{\text{E}}^{\text{o}}

values are more positive are more favourable.
As we can see from then electrode potential data, that reduction of

{Al}^{+}

is spontaneous, but reduction of

{Tl}^{+}

is not. So, we can conclude from this that

\text{T}{\text{l}}^{+}

is more stable than

\text{A}{\text{l}}^{+}