In an estimation of sulphur by Carius method 0.2 g of the substance gave 0.6 g of BaSO₄ . The percentage of sulphur in the substance is _____ %. (Given molar mass in g mol ⁻¹ S : 32 , BaSO₄ : 233 )

Step-by-step solution

Mass of the organic compound, W = 0.2 g Mass of BaSO ₄ formed, m = 0.6 g Molar mass of BaSO ₄ = 233 g mol ⁻¹ Molar mass of S = 32 g mol ⁻¹ The percentage of sulphur in the organic compound is given by the formula: % S = 32 233 m W 100 Substituting the given values: % S = 32 233 0.6 0.2 100 % S = 32 233 3 100 % S = 9600 233 41.20 % Rounding off to the nearest integer, the percentage of sulphur is 41 . Answer: 41