In sulphur estimation, 2.0 10⁻³ mol of an organic compound (X) (molar mass 76 g mol ⁻¹ ) gave 0.4813 g of barium sulphate (molar mass 233 g mol ⁻¹ ). The percentage of sulphur in the compound (X) is ______ 10⁻¹ % (Nearest integer)

Step-by-step solution

Mass of the organic compound (X) can be calculated as: Mass of X = Moles Molar mass Mass of X = 2.0 10⁻³ mol 76 g mol ⁻¹ = 0.152 g In the Carius method for sulphur estimation, the mass of sulphur in the given mass of BaSO ₄ is: Mass of S = 32 233 Mass of BaSO ₄ Mass of S = 32 233 0.4813 g 0.0661 g The percentage of sulphur in the organic compound is given by: % of S = Mass of S Mass of X 100 % of S = 0.0661 0.152 100 43.487 % To express this in the requested format: 43.487 % = 434.87 10⁻¹ % Rounding to the nearest