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CORRECT order of stability for the following is CH ₂= CH ⁻, CH ₃- CH ₂⁻, CH C ⁻

Options

  1. ACH ₂= CH ⁻> CH C ⁻> CH ₃- CH ₂⁻
  2. BCH C ⁻> CH ₂= CH ⁻> CH ₃- CH ₂⁻
  3. CCH C ⁻> CH ₃- CH ₂⁻> CH ₂= CH ⁻
  4. DCH ₃- CH ₂⁻> CH ₂= CH ⁻> CH C ⁻

Correct answer

B. CH C ⁻> CH ₂= CH ⁻> CH ₃- CH ₂⁻

Step-by-step solution

Carbanion stability is determined by the s-character of the hybrid orbital bearing the negative charge. The acetylide anion CH C^- has the carbanion on an sp hybridized carbon (50% s-character), providing optimal stabilization through efficient overlap with the charged orbital. The vinyl anion CH₂ = CH^- has the carbanion on an sp² hybridized carbon (33% s-character), offering moderate stabilization. The primary alkyl anion CH₃ - CH₂^- has the carbanion on an sp³ hybridized carbon (25% s-character), providing the l

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