JEE Main 202622 JanuaryEvening Shift
- Exam
- JEE Main
- Year
- 2026
- Date
- 22 January
- Shift
- Evening Shift
- Subject
- Chemistry
- Chapter
- General Organic Chemistry
JEE Main 2026 · 22 January · Evening Shift · Chemistry · General Organic Chemistry
The IUPAC name of the following compound is :
The IUPAC name of the following compound is :
Options
- An-propyl-2-bromo-5-methylheptanoate
- Bn-propyl-1-bromo-4-methylhexanoate
- C2-bromo-5-methylpropanoate
- D2-bromo-5-methylhexylpropanoate
Correct answer
A. n-propyl-2-bromo-5-methylheptanoate
Step-by-step solution
The main functional group is an ester (COO-).
The alcohol part is n-propanol, giving an n-propyl ester.
For the acid part, identify the longest carbon chain: Starting from the carbonyl carbon (C1):
C(=O)-CHBr (C2)-CH₂ (C3)-CH(with two methyls).
The isopropyl group represents two methyl branches on C4.
The longest continuous chain through the main skeleton and maximizing chain length is 7 carbons, making it a heptanoate.
Numbering from the carbonyl: C1-C2(Br)-C3-C4-C5(methyl substituent)-C6-C7.
Therefore, the IUPAC name is n-propyl 2-bromo-5-methylheptanoate.
The alcohol part is n-propanol, giving an n-propyl ester.
For the acid part, identify the longest carbon chain: Starting from the carbonyl carbon (C1):
C(=O)-CHBr (C2)-CH₂ (C3)-CH(with two methyls).
The isopropyl group represents two methyl branches on C4.
The longest continuous chain through the main skeleton and maximizing chain length is 7 carbons, making it a heptanoate.
Numbering from the carbonyl: C1-C2(Br)-C3-C4-C5(methyl substituent)-C6-C7.
Therefore, the IUPAC name is n-propyl 2-bromo-5-methylheptanoate.