JEE Main 202622 JanuaryMorning Shift
- Exam
- JEE Main
- Year
- 2026
- Date
- 22 January
- Shift
- Morning Shift
- Subject
- Chemistry
- Chapter
- General Organic Chemistry
JEE Main 2026 · 22 January · Morning Shift · Chemistry · General Organic Chemistry
Sodium fusion extract of an organic compound (Y) with CHCl_ 3 and...
Sodium fusion extract of an organic compound with and chlorine water gives violet color to the layer. 0.15 g of gave 0.12 g of the silver halide precipitate in Carius method. Percentage of halogen in the compound is . (Nearest integer)
(Given : molar mass \mathrm{I})
(Given : molar mass \mathrm{I})
Correct answer
0
Step-by-step solution
The sodium fusion extract gives violet color with CHCl₃ and chlorine water, indicating the presence of iodine.
In the Carius method, 0.15 g of compound Y produces 0.12 g of silver halide precipitate (AgI).
Molar mass of AgI = 108 + 127 = 235 g/mol.
Moles of AgI = 0.12 / 235 = 0.000510 mol.
Since each AgI contains one I atom, moles of I = 0.000510 mol.
Mass of I = 0.000510 × 127 = 0.0647 g.
Percentage of halogen (iodine) in compound Y
= (0.0647 / 0.15) × 100 = 43.1%, which rounds to 43% (nearest integer).
In the Carius method, 0.15 g of compound Y produces 0.12 g of silver halide precipitate (AgI).
Molar mass of AgI = 108 + 127 = 235 g/mol.
Moles of AgI = 0.12 / 235 = 0.000510 mol.
Since each AgI contains one I atom, moles of I = 0.000510 mol.
Mass of I = 0.000510 × 127 = 0.0647 g.
Percentage of halogen (iodine) in compound Y
= (0.0647 / 0.15) × 100 = 43.1%, which rounds to 43% (nearest integer).