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JEE Main 202621 JanuaryMorning Shift
Exam
JEE Main
Year
2026
Date
21 January
Shift
Morning Shift
Subject
Chemistry
Chapter
General Organic Chemistry

JEE Main 2026 · 21 January · Morning Shift · Chemistry · General Organic Chemistry

In Carius method, 0.75 g of an organic compound gave 1.2 g of...

In Carius method, 0.75 g of an organic compound gave 1.2 g of barium sulphate, find percentage of sulphur (molar mass 32 g mol−132 \mathrm{~g} \mathrm{~mol}^{-1}). Molar mass of barium sulphate is 233 g mol−1233 \mathrm{~g} \mathrm{~mol}^{-1}.

Options

  1. A10.30%
  2. B16.48%
  3. C21.97%
  4. D4.55%4.55 \%

Correct answer

C. 21.97%

Step-by-step solution

In Carius method, sulfur is converted to BaSO4BaSO_4. Each mole of BaSO4BaSO_4 contains 1 mole of S.
Mass of S = 32233×1.2=0.1648\frac{32}{233} \times 1.2 = 0.1648 g
Percentage of S = 0.16480.75×100=21.97%\frac{0.1648}{0.75} \times 100 = 21.97\%
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