In Carius method, 0.75 g of an organic compound gave 1.2 g of barium sulphate, find percentage of sulphur (molar mass 32 ~g ~mol ⁻¹ ). Molar mass of barium sulphate is 233 ~g ~mol ⁻¹ .

Step-by-step solution

In Carius method, sulfur is converted to BaSO₄ . Each mole of BaSO₄ contains 1 mole of S. Mass of S = 32 233 1.2 = 0.1648 g Percentage of S = 0.1648 0.75 100 = 21.97 %