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JEE Main 20254 AprilMorning Shift
Exam
JEE Main
Year
2025
Date
4 April
Shift
Morning Shift
Subject
Chemistry
Chapter
General Organic Chemistry

JEE Main 2025 · 4 April · Morning Shift · Chemistry · General Organic Chemistry

In Dumas' method for estimation of nitrogen 1 g of an organic...

In Dumas' method for estimation of nitrogen 1 g of an organic compound gave 150 mL of nitrogen collected at 300 K temperature and 900 mm Hg pressure. The percentage composition of nitrogen in the compound is _____ %\% (nearest integer).
(Aqueous tension at 300 K=15 mmHg300 \mathrm{~K}=15 \mathrm{~mm} \mathrm{Hg})

Correct answer

0

Step-by-step solution

Partial pressure of N2=(900−15)=885 mmHg\mathrm{N}_2=(900-15)=885 \mathrm{~mm} \mathrm{Hg}
Mole of N2=(885760×0.15)(0.0821×300)=0.0071\mathrm{N}_2=\frac{\left(\frac{885}{760} \times 0.15\right)}{(0.0821 \times 300)}=0.0071
Moles %\% of nitrogen in organic compound
<br/>=(0.0071×28)1×10<br>=19.85%<br/>\begin{aligned}<br />& =\frac{(0.0071 \times 28)}{1} \times 10 \\<br>& =19.85 \%<br />\end{aligned}
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