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JEE Main 20253 AprilMorning Shift
Exam
JEE Main
Year
2025
Date
3 April
Shift
Morning Shift
Subject
Chemistry
Chapter
General Organic Chemistry

JEE Main 2025 · 3 April · Morning Shift · Chemistry · General Organic Chemistry

During estimation of nitrogen by Dumas' method of compound X(0.42...

During estimation of nitrogen by Dumas' method of compound X(0.42 g)\mathrm{X}(0.42 \mathrm{~g}) :
During estimation of nitrogen by Dumas' method of compound X(0.42 ~g) : _____ mL of N_2 gas will be liberated at STP.
_____ mL of N2\mathrm{N}_2 gas will be liberated at STP. (nearest integer)
(Given molar mass in gmol−1:C:12,H:1\mathrm{g} \mathrm{mol}^{-1}: \mathrm{C}: 12, \mathrm{H}: 1, N:14)\mathrm{N}: 14)

Correct answer

0

Step-by-step solution

M.wt. of given compound =86=86Applying POAC on ' N 'nX×2=nN2×2&0.4286=nN2&⇒( Volume )N2 at STP=0.4286×22.4L&=0.1108L=110.8mℓ\begin{aligned}& \mathrm{n}_{\mathrm{X}} \times 2=\mathrm{n}_{\mathrm{N}_2} \times 2 \& \frac{0.42}{86}=\mathrm{n}_{\mathrm{N}_2} \& \Rightarrow(\text{ Volume })_{\mathrm{N}_2} \text{ at } \mathrm{STP}=\frac{0.42}{86} \times 22.4 \mathrm{ L} \& =0.1108 \mathrm{ L}=110.8 \mathrm{ m} \ell\end{aligned}
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