In the sulphur estimation, 0.20 g of a pure organic compound gave 0.40 g of barium sulphate. The percentage of sulphur in the compound is ______ 10⁻¹ % . (Molar mass : O =16, ~S =32, Ba =137 in g mol ⁻¹ )

Step-by-step solution

array ll Organic Compound & BaSO ₄ 0.20 gm & 0.40 gm & 0.40 233 ~mol ( BaSO ₄ ) & 0.40 233 ~mol (Sulphur) & 0.40 233 32 gm (sulphur) array % ~S = 0.40 32 233 100 0.20 =27.5 % or 275 10⁻¹ %