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JEE Main 202529 JanuaryEvening Shift
Exam
JEE Main
Year
2025
Date
29 January
Shift
Evening Shift
Subject
Chemistry
Chapter
General Organic Chemistry

JEE Main 2025 · 29 January · Evening Shift · Chemistry · General Organic Chemistry

In the sulphur estimation, 0.20 g of a pure organic compound gave...

In the sulphur estimation, 0.20 g of a pure organic compound gave 0.40 g of barium sulphate. The percentage of sulphur in the compound is ______ ×10−1%\times 10^{-1} \%. (Molar mass : O=16, S=32,Ba=137\mathrm{O}=16, \mathrm{~S}=32, \mathrm{Ba}=137 in gmol−1\mathrm{g} \mathrm{mol}^{-1} )

Correct answer

0

Step-by-step solution

 Organic Compound ⟶BaSO40.20gm0.40gm0.40233mol(BaSO4)0.40233mol (Sulphur) 0.40233×32gm (sulphur) \begin{array}{ll}\text{ Organic Compound } \longrightarrow & \mathrm{BaSO}_4 \\ 0.20 \mathrm{gm} & 0.40 \mathrm{gm} \\ & \frac{0.40}{233} \mathrm{ mol}\left(\mathrm{BaSO}_4\right) \\ & \frac{0.40}{233} \mathrm{ mol} \text{ (Sulphur) } \\ & \frac{0.40}{233} \times 32 \mathrm{gm} \text{ (sulphur) }\end{array}\% \mathrm{ S}=\frac{\frac{0.40 \times 32}{233} \times 100}{0.20}=27.5 \%oror275 \times 10^{-1} \% $
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