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During " S " estimation, 160 mg of an organic compound gives 466 mg of barium sulphate. The percentage of Sulphur in the given compound is _______ %. (Given molar mass in g mol ⁻¹ of Ba : 137, ~S : 32, O : 16 )

Correct answer

0

Step-by-step solution

aligned & m mole of BaSO ₄= mmoles of S = 466 233 & Mass of S = 466 233 32 mg & =64 mg & % ~S = 64 160 100=40 % aligned

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