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JEE Main 202522 JanuaryMorning Shift
Exam
JEE Main
Year
2025
Date
22 January
Shift
Morning Shift
Subject
Chemistry
Chapter
General Organic Chemistry

JEE Main 2025 · 22 January · Morning Shift · Chemistry · General Organic Chemistry

In Carius method for estimation of halogens, 180 mg of an organic...

In Carius method for estimation of halogens, 180 mg of an organic compound produced 143.5 mg of AgCl . The percentage composition of chlorine in the compound is _______ \%. (Given : molar mass in gmol−1\mathrm{g} \mathrm{mol}^{-1} of Ag:108,Cl:35.5\mathrm{Ag}: 108, \mathrm{Cl}: 35.5 )

Correct answer

0

Step-by-step solution

nCl=nAgCl=143.5×10−3143.5=10−3%Cl=10−3×35.5180×10−3×100=19.72\begin{aligned} & \mathrm{n}_{\mathrm{Cl}}=\mathrm{n}_{\mathrm{AgCl}}=\frac{143.5 \times 10^{-3}}{143.5}=10^{-3} \\ & \% \mathrm{Cl}=\frac{10^{-3} \times 35.5}{180 \times 10^{-3}} \times 100=19.72\end{aligned}
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