Number of optical isomers possible for 2 – chlorobutane ........

Step-by-step solution

The number of optical isomers possible for a compound is 2 n where n = number of asymmetric carbon atoms. As n =1 for 2 - chlorobutane , it is an optically active molecule with one chiral carbon atom and it forms dextro and laevo isomers. 2 n = 2 1 = 2 . Hence, it has two optical isomers.