0 . 400 g of an organic compound ( X ) gave 0 . 376 g of AgBr in Carius method for estimation of bromine. % of bromine in the compound ( X ) is (Given: Molar mass AgBr = 188 g mol - 1 Br = 80 g mol - 1

Step-by-step solution

The percentage composition of element = mass   of   element mass   of   organic   compound × 100 Moles of AgBr = 0 . 376 188 Moles of Br = 0 . 376 188 Mass of Br = 0 . 376 188 × 80 %  of  Br = 0 . 376 × 80 188 × ( 0 . 400 ) × 100 =   40 %