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In sulphur estimation. 0 . 471 g of an organic compound gave 1 . 4439 g of barium sulphate. The percentage of sulphur in the compound is _______(Nearest Integer) (Given: Atomic mass Ba: 137 u : S : 32 u , O : 16 u )

Correct answer

0

Step-by-step solution

Molecular mass of Barium Sulphate( BaSO 4 ) = 233   g % sulphur = 32 233 ×  weight of  BaSO 4  formed   weight of organic compound  × 100 = 32 233 × 1 . 4439 0 . 471 × 100 = 42 . 10 Nearest integer: 42

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