JEE Main202227 Jul 2022Morning ShiftChemistryGeneral Organic ChemistryActual
In Carius method of estimation of halogen. 0 . 45 g of an organic compound gave 0 . 36 g of AgBr . Find out the percentage of bromine in the compound. (Molar masses : AgBr = 188 g mol - 1 : Br = 80 g mol - 1 )
Options
- A34 . 04 %
- B40 . 04 %
- C36 . 03 %
- D38 . 04 %
Correct answer
A. 34 . 04 %
Step-by-step solution
The Carius halogen method in analytical chemistry is a method for the quantitative determination of halogens in chemical substances. A known mass of an organic compound is heated with fuming nitric acid in the presence of silver nitrate contained in a hard glass tube known as Carius tube, in a furnace. Mass of organic compound = 0 . 45 gm Mass of AgBr obtained = 0 . 36 gm ∴ Moles of AgBr = 0 . 36 188 ∴ Mass of Bromine = 0 . 36 188 × 80 = 0 . 1532 gm ∴   %   Br in compound = 0 . 1532