JEE Main202127 Jul 2021Morning ShiftChemistryGeneral Organic ChemistryActual
An organic compound is subjected to chlorination to get compound A using 5 . 0 g of chlorine. When 0 . 5 g of compound A is reacted with AgNO 3 [Carius Method], the percentage of chlorine in compound A is when it forms 0 . 3849 g of AgCl . (Round off to the Nearest Integer) (Atomic masses of Ag and Cl are 107 . 87 and 35 . 5 respectively)
Correct answer
0
Step-by-step solution
n Cl in compound = n AgCl = 0 . 3849   g ( 107 . 87 + 35 . 5 ) g / mol ⇒ mass of chlorine = n Cl × 35 . 5 = 0 . 0953 gm ⇒ % wt. of chlorine = 0 . 0953 0 . 5 × 100 = 19 . 06 %