When 0 . 15 g of an organic compound was analyzed using Carius method for estimation of bromine, 0 . 2397 g of AgBr was obtained. The percentage of bromine in the organic compound is _________.(Nearest integer) [Atomic mass : Silver = 108 , Bromine = 80 ]

Step-by-step solution

Moles of Br = Moles of AgBr obtained ⇒ Mass of Br = 0 . 2397 188 × 80   g therefore % Br in the organic compound = W Br W T × 100 = 0 . 2397 × 80 188 × 0 . 15 × 100 = 0 . 85 × 80 = 68 ⇒ Nearest integer is ' 68 '