In Duma's method of estimation of nitrogen, 0 . 1840 g of an organic compound gave 30 mL of nitrogen collected at 287 K and 758 mm of Hg pressure. The percentage composition of nitrogen in the compound is ______. (Round off to the Nearest Integer). [Given : Aqueous tension at 287 K = 14 mm of Hg ]

Step-by-step solution

In Duma's method of estimation of Nitrogen. 0 . 1840   gm of organic compound gave 30   mL of nitrogen which is collected at 287   K and 758   mm of Hg . Given ; Aqueous tension at 287   K = 14   mm of Hg . Hence, actual pressure = 758 - 14 = 744   mm of Hg . Volume of nitrogen at STP = 273 × 744 × 30 287 × 760 V = 27 . 935   mL ∵   22400   mL of N 2 at STP weighs = 28   gm . ∴   27 . 94   mL of N 2 at STP weighs = 28 22